Andreas Blog
Thursday, March 5, 2015
Assignment #15
1) 0^0 = 1 because anything raised to the 0 is one (x^0=1).
2)
a) T5(x) = (x^2/2) + (x^3/6) + (x^4/24) + (x^5/120)
b) T5(x) = (x^2) - (x^3/6) + (x^5/120)
c) T5(x) = (-x^2/2) + (x^4/24)
1 comment:
Unknown
March 7, 2015 at 2:24 PM
You were supposed to have 5 terms for each series
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You were supposed to have 5 terms for each series
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